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x^2+4x=525
We move all terms to the left:
x^2+4x-(525)=0
a = 1; b = 4; c = -525;
Δ = b2-4ac
Δ = 42-4·1·(-525)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-46}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+46}{2*1}=\frac{42}{2} =21 $
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